Aptitude preparation
Aptitude on Time and Work
Aptitude questions and answers on Time and Work


1. A can do a piece work in 10 days, Then what will be the A's 1 day work ? 

Correct Answer:Option
B
Explanation:
A can do a piece work in 10 days, A's 1 day work = 1/10.
A can do a piece work in n days, Then A's 1 day work = 1/n.
2. A and B together can complete a piece of work in 6 days.If A alone can complete the work in 15 days, in how many days can B alone complete that work ? 

Correct Answer:Option
A
Explanation:
(A+B ) 1 day's work = 1/6 , A's 1 day's work = 1/15 , B's 1 day's work = ?
B's 1 day's work = (A+B )  A ,
B's 1 day's work = (1/6)  (1/15) > (52) / 30 = 3/30 = 1/10.
B's 1 day's work = 1/10
Hence , B alone can complete the work in 10 days.
3. A can do a piece of work in 6 days of 8 hours each and B can do it in 5 days of 6 hours each.How long will they taketo do it , working together 2 4/13 hours a day ? 

Correct Answer:Option
B
Explanation:
A can complete the work in (6*8) = 48 , A's 1 hour's work = 1/48.
B can complete the work in (5*6) = 30 , B's 1 hour's work = 1/30.
(A+B) 1 hour's work = (1/48)+(1/30) = (5+8) / 240 =13/240.
Therefore Both will finish work in 240/13 hours.
Number of days of 2(4/13) hrs each = (240/13)*(13/30) = 8 days.
4. A can do a work in 40 days.He worked for 5 days then B finished in 21 days.In how many days can A and B together finish the work ? 

Correct Answer:Option
C
Explanation:
A's 5 days work = 5/40 = 1/8 , Remaining work = 1  1/8 = 7/8.
B's 21 days work = 7/8.
B's 1 day work = (1/21) * (7/8) = 1/24.
(A+B)'s 1 day work = 1/40 + 1/24 = 1/15.
A and B can do the whole work in 15 days.
5. A is half good a man as B and together they finish a job in 16 days.In how many days working alone will B finish the job ? 

Correct Answer:Option
D
Explanation:
Let B can do the work in x days and A can do the work in 2x days.
Then, (1/x)+(1/2x) = 1/16 > x = (3/2)*16 =24 days.
6. 4 men and 2 boys can do a piece of work in 8 days while 6 men and 2 boys can do the same work in 7 days.In how many days can 3 men and 3 boy do the work? 

Correct Answer:Option
A
Explanation:
: Let 1 man’s 1 day’s work = x and 1 boy’s 1 day’s work = y.
Then, 4x+2y =1/8 and 6x+2y = 1/7.
Solving,we get: x = 1/84 and y = 1/28.
(3 men + 3 boy)’s 1 day’s work = (3x 1/84 + 3 x 1/28 ) =11/84
So, 3 men and 3 boy together can finish the work in 84/11 =7 7/11 days.
7. A pot has two holes. The first hole emptied the pot in 9 minutes where as second hole emptied the pot in 6 minutes. If water leaks out at a constant rate, How much time needed to emptied the pot by both the holes?

A.

2.6 minutes

B.

3.6 minutes

C.

0.6 minutes

D.

1.6 minutes


Correct Answer:Option
B
Explanation:
1 minute’s work of both the holes = 1/9 + 1/6 = 5/18 .
So, both the punctures will emptied the pot in 18/5 = 3.6 minutes.
8. Ram can do a work in 20days, Sam can do the same work in 30days where as Prem can do the same work in 40days. How much time needed for Ram, Sam and Prem to finish the work?

A.

9.2 days

B.

3.6 days

C.

8.1 days

D.

9.6 days


Correct Answer:Option
A
Explanation:
1 day’s work of the three persons = 1/20 + 1/30 + 1/40 = 13/120 .
So, all the three together will complete the work in 120/13 ≈ 9.2 days.
9. Amulya can do a piece of work in 35 days. Surya is 25% more efficient than Amulya. The number of days taken by Surya to do the same piece of work is?


Correct Answer:Option
C
Explanation:
Ratio of times taken by Amulya and Surya = 125 : 100 = 5 : 4.
Suppose Surya takes S days to do the work.
5 : 4 : : 35 : S => S = (4 × 35/5) => S = 28 days.
10. Gagan and Gamya can together finish a work in 80 days. They worked together for 40 days and then Gamya left. After another 60 days, Gagan finished the remaining work. In how many days Gagan alone can finish the job?


Correct Answer:Option
C
Explanation:
(Gagan+ Gamya)’s 20 days work = 1/80 × 40 = 1/2 .
Remaining work = 1  1/2 = 1/2 .
Now, 1/2 work is done by Gagan in 60 days.
Whole work will be done by A in (60 × 2) = 120 days.
11. A, B and C together earn Rs. 3000 per day, while A and C together earn Rs. 1880 and B and C together earn Rs. 1520. The daily earning of C is ? 
A.

Rs. 450

B.

Rs. 500

C.

Rs. 420

D.

Rs. 400


Correct Answer:Option
D
Explanation:
B’s daily earning = Rs. (3000  1880) = Rs. 1120.
A’s daily earning = Rs. (3000  1520) = Rs. 1480.
C’s daily earning = Rs.[ 3000  (1120 + 1480) ] = Rs. 400.
12. Amulya, Surya and Ramu can do a piece of work in 360, 540 and 720 days respectively. They started the work but Amulya left 8 days before the completion of the work while Surya left 12 days before the completion. Find the number of days Ramu worked ? 
A.

262.5 days

B.

172.5 days

C.

222.5 days

D.

162.5 days


Correct Answer:Option
D
Explanation:
Suppose the work was finished in R days.
Then, Amulya’s (R  8) days work + Surya’s (x  12) days work + Ramu’s R days work = 1
=> (R  8) / 360 + (R  12) / 540 + R / 720 = 1 ==> 6 (R  8) + 4 (R  12) + 3R = 2160.
13R = 2114 => R = 162.5 days.
So Ramu worked for 162.5 days.
13. 10 Men can complete a work in 70 days and 10 women take 140 days to complete the work. How many days will 5 men and 10 women take to complete the work? 
A.

60 days

B.

70 days

C.

20 days

D.

80 days


Correct Answer:Option
B
Explanation:
One day work of one man = 1/700 ;
One day work of one woman = 1/1400 .
One day work of (5 men + 10 women)’s = 5/700 + 10/1400 = 1/140 + 1/140 = 1/70 .
So 5 men and 10 women can complete the work in 70 days.
14. 5 boys and 2 girls working together can finish a work four times faster than of as one boy and one girl. Find the working capacity ratios of boy and girl? 

Correct Answer:Option
B
Explanation:
Let us assume 1 boy’s 1 day’s work = B ;
AND 1 girl’s 1 day’s work = G .
According to the question,
5B + 2G = 4 (B + G) => B = 2G => B/G = 2/1 .
So the working capacity ratios of boy and girl is 2:1
15. If 12 Atype machines and 16 Btype machines can finish a work in 5 days; 13 Atype machines and 24 Btype machines can finish the same work in 4 days, then find the ratio of the daily work done by Atype machine to that of Btype machine ? 

Correct Answer:Option
B
Explanation:
Let 1 Atype machines’s 1 day’s work = a ;
1 Btype machines’s 1 day’s work = b .
Then, 12a + 16b = 1/5 and 13a + 24b = 1/4 .
After solving above equations we will get a = 1/100 and b = 1/200 .
So a : b = 1/100 : 1/200 = 2 : 1.
16. 10 Seniors and 15 Juniors together can complete a work in 6 days. It takes 100 days for one Senior alone to complete the work. How many days will be needed for one Junior alone to complete the work? 
A.

225 days

B.

234 days

C.

215 days

D.

235 days


Correct Answer:Option
A
Explanation:
Be focus while understanding the explanation.
1 Senior’s 1 day’s work = 1/100 .
(10 Senior + 15 Junior)’s 1 day’s work = 1/6 .
15 Junior’s 1 day’s work = 1/6  10/100 = 1/6  1/10 = 1/15 .
1 Junior’s 1 day’s work = 1/225 .
So, 1 Junior alone can complete the work in 225 days.
17. A, B and C can finish a work for Rs. 1450. A and B together get 21/54 of the amount, How much amount will C paid? 
A.

Rs. 806

B.

Rs. 886

C.

Rs. 816

D.

Rs. 880


Correct Answer:Option
B
Explanation:
Amount paid to C = 1  21/54 of 1450 = 33/54 of 1450.
So, C’s share = Rs. 33/54 × 1450 = Rs. 886.
18. Ramya works two times fast as Rajani. If Rajini alone can complete a work in 12 days, find the number of days in which Ramya and Rajani can together finish the work ? 
A.

4 days

B.

6 days

C.

14 days

D.

24 days


Correct Answer:Option
A
Explanation:
Ratio of rates of working of Ramya and Ralani = 2 : 1.
So, ratio of times taken = 1 : 2.
==> Ramya’s 1 day’s work = 1/6 ; Rajani’s 1 day’s work = 1/12 .
(Ramya + Rajani)’s 1 day’s work = 1/6 + 1/12 = 3/12 = 1/4 .
So, Ramya and Rajani together can finish the work in 4 days.
19. A takes double the time as B or triple the time as C to finish work. A, B and C can finish the work in 2 days. Find how much time needed for B to finish the work alone ? 
A.

4 days

B.

6 days

C.

14 days

D.

24 days


Correct Answer:Option
B
Explanation:
Let us assume A work time = x days
According to the question,
A, B and C take x, x/2 and x/3 days to complete the work.
So, ( 1/x + 2/x + 3/x ) = 1/2 => 6/x = 1/2 => x = 12.
So, B takes ( x/2 = 12/2 ) => 6 days to finish the work.
20. Anthony can finish a work in 18 days and Bharath can do the same work in 9days. Find how much work can be done by both Anthony and Bharath in one day? 

Correct Answer:Option
C
Explanation:
Anthony’s 1 day’s work = 1/18
Bharath’s 1 day’s work = 1/9 .
(Anthony + Bharath)’s 1 day’s work = 1/18 + 1/9 = 1/6 .
Anthony and Bharath together can finish 1/6 part of the work in a single day.
Any Suggestions To This Page